1.Two charges, q1 = −3.00 mC and q2 = 4.50 mC, are located at −2.00 cm and 3
ID: 2111292 • Letter: 1
Question
1.Two charges, q1 = −3.00 mC and q2 = 4.50 mC, are located at −2.00 cm and 3.00 cm on the x axis, respectively. What are the magnitude and direction of the resulting field at (a) x = −3.00 cm? (b) x = 0 cm? (c) x = 5.00 cm?
2. Van de Graaff accelerators use static electricity to accelerate particles to high energies. A typical electric field in a Van de Graaff accelerator is 2.50×10^6 N/C. (a) What is the magnitude of the force on an electron in this field? (b) How about on an alpha particle, which carries a charge of 2e?
Explanation / Answer
a) E = Kq/r^2
so at x = -3 cm
E = K(3)E-3 / 0.01^2 - K(4.5)E-3 / 0.06^2 = 2.5E11 N/C towards + x axis
b) at x=0
E = K(3)E-3 / 0.02^2 + K(4.5)E-3 / 0.03^2 = 1.12E11 N/c _ x axis
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.