Answer On the highway a car accelerates from its initial velocity vo= 5 m/s to r

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On the highway a car accelerates from its initial velocity vo= 5 m/s to reach the velocity of Vf= 25 m/s in t=25 seconds. What is the value of the acceleration a (m/s ) ? What is the magnitude of the force F that is exerted by the driver to the back of the car's seat if the driver's mass is m = 75 kilograms ? HINT: use the second Law of Newton to calculate the force and the data from part (A). The car moves with the constant velocity of vf = 25 m/s on a straight road the distance of d = 95 kilometers. How soon (in hours) the car will cover this distance ? HINT: Recall that 1 km = 1000 meters. 1 h = 60 min, 1 min = 60 seconds.

Explanation / Answer

A) From newtons law of motion, V(final)= V(initial) + acceleration x time hence a = (vfinal - vinitial) / time

B) from newtons 2nd law, Force= mass x acceleration = 75 x acceleration from 1st part

C) d= 95 km = 95 x 1000 m as 1km =1000m Now, vfinal = distance / time ; hence time= distance / Vf

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