A blacksmith heats a 2.0 kg iron horseshoe to 420 degrees celcius , then plunges

Question

A blacksmith heats a 2.0 kg iron horseshoe to 420 degrees celcius , then plunges it into a bucket containing 16 kg of water at 18 degrees celcius . The specific heat of iron is 447 J/kgK. What is the final temperature? Express your answer using two significant figures. A blacksmith heats a 2.0 kg iron horseshoe to 420 degrees celcius , then plunges it into a bucket containing 16 kg of water at 18 degrees celcius . The specific heat of iron is 447 J/kgK. What is the final temperature? Express your answer using two significant figures. What is the final temperature? Express your answer using two significant figures.

Explanation / Answer

H=m*c*dT

given Cfe=447 j/kgK

Cwater= 4186 J/kg K

Hfe=2*447*dTfe

Hwater=16*4186*dTwater

let final temp of both =T1

Hfe=Hwater

=>2*447*(420-T1)=16*4186*(T1-18)

894(420-T1)=66976(T1-18)

375480-894T1=66976T1-1205568

1581048=67870T1

T1=23.29 C

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