A blacksmith uses the heat energy from an oven to heat steel and other metals. I

Question

A blacksmith uses the heat energy from an oven to heat steel and other metals. Increasing the temperature makes it easier to form a metal into a desired shape, such as a horseshoe. The blacksmith also uses water to cool a hot horseshoe to room temperature. A steel horseshoe of mass 0.05kg at a temperature of 800K (“red hot”) is dropped into 73 a bucket of water (mass 1.0kg) at 300K (“room temperature”). What is the final temperature of the horseshoe and water? You may assume that no water is converted into steam.

Explanation / Answer

Given data: mshoemshoe =0.50 kg TshoeTshoe =800 K mwatermwater =1.0 kg TwaterTwater =300 K Assumptions: Specific heat remains constant. Concept Used : Heat rejected by the horseshoe will be equal to the heat received by the water. calculations : Let final temperature of the horseshoe and the water becomes TfTf Heat rejected by the horseshoe = mshoecshoe(TshoeTf)mshoecshoe(TshoeTf) Again,heat received by the water.= mwatercwater(TfTwater)mwatercwater(TfTwater) Now taking Cshoe=450J/Kg.KCshoe=450J/Kg.K Cwater=4186J/Kg.KCwater=4186J/Kg.K Therefore, we have mshoecshoe(TshoeTf)mshoecshoe(TshoeTf) = mwatercwater(TfTwater)mwatercwater(TfTwater) 0.5450(800Tf)=1.04186(Tf300)0.5450(800Tf)=1.04186(Tf300) 800Tf=18.6044(Tf300)=18.6044Tf5581.33800Tf=18.6044(Tf300)=18.6044Tf5581.33 So, Tf=325.51KTf=325.51KTherefore, final temperature of the water and horseshoe = 325.51 K Part 2: Given data: mshoemshoe=2.0kg TshoeTshoe =800 K mwatermwater =1.0 kg TwaterTwater =300 K TfTf =373 K Assumptions: Specific heat remains constant

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.