Two narrow slits of width a are separated by a center-to-center distance d. Supp

Question

Two narrow slits of width a are separated by a center-to-center distance d. Suppose that the ratio of d to a is an integer, d/a=m.

(a) Show that the diffraction pattern produced by this arrangement of slits, the m-th interference maximum (corresponding to d*sin(theta)=m*(wavelength) is suppressed because of coincidence with a diffraction minimum. Show that this is also true for the 2m-th, 3m-th, etc., interference maxima.

(b) How many interference maxima are there between one diffraction minimum on one side and the next on the same side?

Explanation / Answer

As d/a = m is an integer therefore the diffraction produced by the slits is m-th interference maximum. as m is an integer this is also true for the 2m-th, 3m-th, etc., interference maxima. the number of interference maxima are 10 on one diffraction minimum on one side and another 10 on the next on the same side.

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