How many grams of ice at - 17 °C must be added to 416 grams of water that is ini

Question

How many grams of ice at -17 °C must be added to 416 grams of water that is initially at a temperature of 92 °C to produce water at a final temperature of 7 °C? Assume that no heat is lost to the surroundings and that the container has negligible mass. The specific heat of liquid water is 4190 J/kg ∙ °C and of ice is 2000 J/kg ∙ °C. For water the normal melting point is 0 °C and the heat of fusion is 334 it × 103 J/kg. The normal boiling point is 100 ° C and the heat of vaporization is 2.256 × 106 J/kg.

Explanation / Answer

0.416*4190(92-7)=m*2000(0+17)=m*334000+m*4190*(7-0)

m=0.3728kg

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