the howler monkey is the lowdest land animal and can be heard up at distances up

Question

the howler monkey is the lowdest land animal and can be heard up at distances up to 9.8km. Assume the acoustic output power of the monkey is uniform in all directions. (Take 10^-12W/m^2 to be the minimal sound intensity level heard be people.

A) Draw a diagram of the problem, and label relevant known and unknown values?

B) At what distance will the sound intensity level be 25dB?

C) If the frequency is 1000Hz, how many wavelengths are there between the monkey and the limit of hearing?

Explain your reasoning please

Explanation / Answer

Part B)

Start with B = 10log I/Io

25 = 10log I/1 X 10^-12

I = 3.16 X 10^-10 W/m^2

Since the intensity at 9800 m is 1 X 10^-12, we can find the power

P = IA = (1 X 10^-12)(4pi)(9800)^2 = 1.207 X 10^-3 Watts

I = P/A

3.16 X 10^-10 = 1.207 X 10^-3/(4pi)(r^2)

r = 551 m

Part C)
v = f(wavelength)

343 = (1000)(wavelength)

wavelength = .343m

9800/.343 = 28571 wavelengths (2.86 X 10^4 wavelengths)

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