HELP PLZ You want to throw a 500 gram rock through a third story window in such

Question

HELP PLZ

You want to throw a 500 gram rock through a third story window in such a way that it travels horizontally through the window. You can throw the ball at 22 m/s and when you release the ball it is 10.0 m below the window. Show your reasoning. No credit for plug and chug into the range formula, or any other cookbook formula.) At what angle from the horizontal must you throw the ball? How far away from the building must you stand to throw it? What energy must you give the ball, relative to its release point? What kinetic energy does it have just before it hits the window? The position of a five gram mass is given by r(t) = Asin(3t) i-hat + Bcos(2t) j-hat + C k-hat A, B, and C are constant lengths, i-hat is the unit vector in the x-direction, etc. In terms of A, B, and C, How far from the origin is the particle at t=0? What is its velocity at t=0? What is the force on it at t=0? What is the force on it at t=phi/4? How long does it take for the x-coordinate to complete one full cycle? How long for the y-coordinate?

Explanation / Answer

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a)

vyf^2 - vyi^2 = -2 g y

==> 0^2 - vyi^2 = -2*9.8*10

==> vyi = 14 m/s

sinTheta = vyi/v = 14/22

==> Theta = 39.521 = 39.5 degrees

b)

t = vyi/9.8 = 14/9.8 = 1.42857 s

x = v cos39.521 t = 22 * 39.521o * 1.42857 = 24.2 m

c)

Ki = 0.5 m v^2 = 0.5 * 0.500 * 22*22 = 121 J

d)

Kf = Ki - m g h = 121 - 0.500*9.8*10 = 72 J

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