A vacuum parallel-plate capacitor has identical disk-shaped plates that are sepa

Question

A vacuum parallel-plate capacitor has identical disk-shaped plates that are separated by 2.0 mm. The area of each plate is 5.0 cm2. The capacitor is being, charged by a constant charging current Ic = 1.8 mA. At t=0, the charge on the plates is zero, Q0 = Q(0) = 0C. (A) At time t = 0.5 mu s, calculate: the charge Q(t) on the plates, the electric field E(t) between the plates, and the potential difference V(t) between the plates. (B) Calculate dE/dt, the time rate of change of the electric field between the plates. (C) Calculate the displacement current density JD between the plates and the displacement current ID. A vacuum parallel-plate capacitor has identical disk-shaped plates that are separated by 2.0 mm. The area of each plate is 5.0 cm2. The capacitor is being, charged by a constant charging current Ic = 1.8 mA. At t = 0, the charge on the plates is zero, Q0 = Q(0) = 0 C. (A) At time t = 0.5 mu s, calculate: the charge Q(t) on the plates, the electric field E(t) between the plates, and the potential difference V(t) between the plates. (B) Calculate dE/dt, the time rate of change of the electric field between the plates. (C) Calculate the displacement current density JD between the plates and the displacement current ID.

Explanation / Answer

Capacitance = epsilon* A/d

   =8.854

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