At a certain point in a pipeline the liquid\'s speed is 8m/s and the gauge press

Question

At a certain point in a pipeline the liquid's speed is 8m/s and the gauge pressure is 7x10^4pa. Find the gauge pressure at the second point in the level 10m lower than at the first if a cross-sectional area is 10cm^2 at first point and 20cm^2 at the second point. The liquid is water. Density of water is 10^3kg/m^3

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Explanation / Answer

from continuity equation; A1 v1 = A2 v2 => 10*10^-4 *8 = 20*10^-4 v => v = 4m/s from bernoulli's equation; P+ density *gh + 0.5 density* v^2 = constant => 7*10^4 + 1000*9.8*0 + 0.5*1000*8^2 = P+ 1000*9.8*(-10)+0.5*1000*4^2 => P = 1.13 Pa

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