A nucleus consists of protons and neutrons confined to a region with a diameter

Question

A nucleus consists of protons and neutrons confined to a region with a diameter of 10^-5 times the diameter of an atom,

L (nucleaus) = 10^-5 x L (atom).

The mass of a proton is 2x10^3 times as large as the mass of an electron, mproton = 2x10^3 x m electron.

Using the information above, is the ground state energy of the proton in the nucleus larger or smaller than the ground state of the electron in an atom.

Professor gave equation: Ee= n^2 h^2 / 8 L^2 me (mass of electron)

idk how to operate this or to get the answers

Explanation / Answer

here n=1 for gorund state

h = 6.626 *10^-34 J/s

L = size of the atom = 10^-5 * 10^-5 = 10^-10 m

me = 2*10^3*9.11*10^-31 kg

so by sub all values

Ee = 6.02 *10^-18 J 0r    37.6 eV

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