A novel human cDNA has been cloned and nucleotide sequence has been determined a

Question

A novel human cDNA has been cloned and nucleotide sequence has been determined as shown below: 5' tcgatgggggcccccgcttcacgcagctgcagtacataatcggc 3' coding 3' agctacacccgggtgcgatgtgcgtcgacgtcatgtattagccg 5' noncoding (template) Write down the mRNA sequence that will be produced from this gene indicating the direction (5' to 3'). Write down the amino acid sequence in the polypeptide chain that will be translated from the mRNA using genetic code dictionary provided in next page. Genetic code Dictionary

Explanation / Answer

Given the nucleotide sequence is : TCGATGGGGGCCCCCGCTTCACGCAGCTGCAGTACATAATCGGC.

Always the DNA sequence contains the nucleotide Adenine (A), Guanine (G), Cytosine (C), Thymine (T).

i) mRNA sequence of the above gene is : UCGAUGGGGGCCCCCGCUUCACGCAGCUGCAGUACAUAAUCGGC.

Always the mRNA sequence contains the nucleotide Adenine (A), Guanine (G), Cytosine (C), Uracil (U).

For the conversion of DNA to mRNA, replace (U) in the place of (T).

ii)The amino acid sequence is: Ser Met Gly Ala Pro Ala Ser Arg Ser Cys Ser Thr Stop Ser

Stop codons are UAA, UGA and UAG.

For the conversion of mRNA sequence to amino acid sequence, split the codons in triplet and find out the codons belong to which amino acid from the genetic code dictionary.

UCG AUG GGG GCC CCC GCU UCA CGC AGC UGC AGU ACA UAA UCG GC

Ser Met Gly Ala Pro Ala Ser Arg Ser Cys Ser Thr Stop Ser

DNA sequence

TCG

ATG

GGG

GCC

CCC

GCT

TCA

CGC

AGC

TGC

AGT

ACA

TAA

TCG

GC

mRNA sequence

UCG

AUG

GGG

GCC

CCC

GCU

UCA

CGC

AGC

UGC

AGU

ACA

UAA

UCG

GC

Amino acid sequence

Ser

Met

Gly

Ala

Pro

Ala

Ser

Arg

Ser

Cys

Ser

Thr

Stop

Ser

DNA sequence

TCG

ATG

GGG

GCC

CCC

GCT

TCA

CGC

AGC

TGC

AGT

ACA

TAA

TCG

GC

mRNA sequence

UCG

AUG

GGG

GCC

CCC

GCU

UCA

CGC

AGC

UGC

AGU

ACA

UAA

UCG

GC

Amino acid sequence

Ser

Met

Gly

Ala

Pro

Ala

Ser

Arg

Ser

Cys

Ser

Thr

Stop

Ser

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