1. An object 3.0 cm tall is placed in front of a concave spherical mirror with a

Question

• 1. An object 3.0 cm tall is placed in front of a concave spherical mirror with a 30 cm radius. Determine the image distance if the object distance is 20 cm.
  
  • 2. An object 3.0 cm tall is placed in front of a concave spherical mirror with a 30 cm radius. Determine the height of the image if the object distance is 20 cm.
    3. An object is placed at 2 m in front of a concave diverging lens. Determine the focal length of the lens given that the image is formed at 40 cm in front of the lens.
    4. For certain studies, converging lens is a good model for human eye. Assume that the focal length of the human lens is 1.7 cm when the eye is relaxed. If an eye is viewing a 2-m-tall tree located 5.1 m in front of the eye, what is the height and orientation of the image on the retina?
    • 
      
    
    

• 2. An object 3.0 cm tall is placed in front of a concave spherical mirror with a 30 cm radius. Determine the height of the image if the object distance is 20 cm.
  3. An object is placed at 2 m in front of a concave diverging lens. Determine the focal length of the lens given that the image is formed at 40 cm in front of the lens.
  4. For certain studies, converging lens is a good model for human eye. Assume that the focal length of the human lens is 1.7 cm when the eye is relaxed. If an eye is viewing a 2-m-tall tree located 5.1 m in front of the eye, what is the height and orientation of the image on the retina?
  • 
    
  
  

Explanation / Answer

1)(1/u)+(1/v)=2/R

or (1/u)+(1/20)=2/30

or u=60 cm

2)m=v/u

=20/60

=1/3

so h'/h=1/3

r h'=3/3

=1 cm

3)(1/200)+(1/20)=1/f

or f=18.1818 cm

4)(1/u)+(1/v)=1/f

or (1/510)+(1/v)=(1/1.7)

or v=1.70569 cm.

so the image of inverted

height of the image=2*(1.70569/510)

=0.006689 m

=0.6689 cm

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.