Two forces, of magnitudes F1 = 70.0 N and F2 = 50.0 N , act in opposite directio

Question

Two forces, of magnitudes F1 = 70.0 N and F2 = 50.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position xi = -1.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm .

A) Find the work W1 done on the block by the force of magnitude F1 = 70.0 N as the block moves from xi = -1.00 cm to xf = 5.00 cm

B) Find the work W2 done by the force of magnitude F2 = 50.0 N as the block moves from xi = -1.00 cm to xf = 5.00 cm

C) What is the net work done on the block by the two forces?

Explanation / Answer

a) W1=F1*(xf-xi)=70*6=420 J

b) W2=F2*(xf-xi)=-50*6=-300J

c) net work done =420-300=120 J

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