A 1 kg block of wood is at rest on a frictionless icy pond. A 10 gram bullet tra
ID: 2098127 • Letter: A
Question
A 1 kg block of wood is at rest on a frictionless icy pond. A 10 gram bullet traveling horizontally with a speed of 1000 m/s enters the block and then exits the block with a horizontal speed of 900 m/s.
1) What is the change in momentum of the bullet/block system (in kg m/s) during the bullet's penetration of the block?
2) What is the change in momentum of the above block (in kg m/s) during the bullet's penetration?
3) What is the speed of the above block (in m/s) when the bullet exits the block?
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Explanation / Answer
1)change in momentum of bullet= .01*100=1 kg-m/s
loss in momentum in bullet =gain in momentum of block;
so change in momentum of block=1 kg-m/s
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