A 0.960 gram sample of a compound is placed in a bomb calorimeter and burned com
ID: 895703 • Letter: A
Question
A 0.960 gram sample of a compound is placed in a bomb calorimeter and burned completely in oxygen. The calorimeter contains 1500 grams of Benzene and the heat capacity of the calorimeter interior (without the Benzene) is 920 Joule/degree celcius. When the compound burns, the temperature goes up from 24.80 degree celcius to 27.10 degree celcius. The molar mass of the compound is 40.0 g/mole. Assuming all of the heat given off in this combustion reaction goes into either the calorimeter or the Benzene, what is the molar heat of combustion of this compound?
Explanation / Answer
Q = m * c * dT
Q = 0.96 g * 920 J/g-degreeC * ( 27.1 - 24.8) degreeC
Q = 2.031 kJ
Now,
Heat of reaction(Q) = n * Cv * dT
2.031 kJ = 0.960 g / 40 g/mol * Cv * ( 27.1 - 24.8) degreeC
Cv = 36.79 kJ/mol-degreeC
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