Now consider three sugar glucose, glucuronic acid, and N acetylglucosamine. Use
ID: 209628 • Letter: N
Question
Now consider three sugar glucose, glucuronic acid, and N acetylglucosamine. Use shorthand eg. Gle(1 4 GleUA8 1 4 G1 NAc) to represent 10 trisaccharides with the sequence Glc - GlcUA-GluNAc. Check all that apply. Gles(4 4)GleUAa(4 4)GlcNAc Gle 1 4)GleUA8(1 6)GlcNAc Glea(1 2)GleUA8(1 3)GlcNAc Glea(1 4)GleUA8(1 3)GlcNAc GIca(1 4)GleUA8(1 6)GlcNAc Glea(1 2)GleUAa(1 3)GlcNAc Glca(1 3)GIcUAa(1 4)GlcNAc Glca(1 2)GleUA8(1 4)GlcNAc Gles(1 3)GleUA8(1 4)GlcNAc Gles(1 4)GleUA8(1 4)GlcNAc Glc3(1 5)GleUA8(1 5)GlcNAc Glca(1 5)GleUAa(1 4)GlcNAc Glca(1 4)GleUAa(1 4)GlcNAc Glca(1 1)GleUAa(1 1)GlcNAc Submit st AnsExplanation / Answer
Amino acids are linked together by peptide bonds. The peptide bond is directional. It is formed between the carboxyl group of an N-terminal amino acid and an amino group of C-terminal amino acid. The polypeptide chain synthesis occurs in N ---> C direction.
For a tripeptide sequence with only three amino acid probabilities A, B and C, each position has 3 different amino acids to occur. So, total number of possibilities = 3 X 3 X 3 = 27
Few examples are,
i. AAA
ii. BBB
iii. CCC
iv. AAB
v. ABB
vi. AAC
vii. ACC
viii. BBA
ix. BAA
x. BBC
xi. BCC
xii. CCA
xiii. CAA
xiv. ABC
xv. ACB
xvi. BCA
xii. BAC
xviii. CAB
xix. CBA
xx. CBB
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