1.) An object moves in a straight line, following the equation x = 5 + 71*t - 5*

Question

1.) An object moves in a straight line, following the equation x = 5 + 71*t - 5*(t^2). Here x is the displacement (in meters), t is the time (in seconds), the symbol "*" means multiplication, and the symbol "^" means "to the power of". What is the velocity, v (in m/s), of the object at time 6 s?

2.) A bowstring is pulled back at a constant speed by an archer, with a force that increases at a constant rate from zero to 105 N. In the process, the bowstring moves back a distance of 14 cm. How much work W (in J) did the archer do?

Explanation / Answer

1) V= 71 - 10 t = 71-60 =11 m/s

2)work done = 1/2(area under f and d)

=1/2(105*0.14)

=7.35J

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