A 1500 W portable heater is needed to replace the heat lost through a circular w

Question

A 1500 W portable heater is needed to replace the heat lost through a circular window in the wall of a home that is made of a single pane of glass 0.30 cm thick. Thermal conductivity for the glass is 0.63 W/m A 1500 W portable heater is needed to replace the heat lost through a circular window in the wall of a home that is made of a single pane of glass 0.30 cm thick. Thermal conductivity for the glass is 0.63 W/m A 1500 W portable heater is needed to replace the heat lost through a circular window in the wall of a home that is made of a single pane of glass 0.30 cm thick. Thermal conductivity for the glass is 0.63 W/m A 1500 W portable heater is needed to replace the heat lost through a circular window in the wall of a home that is made of a single pane of glass 0.30 cm thick. Thermal conductivity for the glass is 0.63 W/m A 1500 W portable heater is needed to replace the heat lost through a circular window in the wall of a home that is made of a single pane of glass 0.30 cm thick. Thermal conductivity for the glass is 0.63 W/m

Explanation / Answer

1500 = 0.63*(change in temperature)*area /thickness

= 0.63*(200-(-120))*pie*r^2/0.30

so, r = 84 cm

ans : 84 cm

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