What is the escape speed on a spherical asteroid whose radius is 575 km and whos

Question

What is the escape speed on a spherical asteroid whose radius is 575 km and whose gravitational acceleration at the surface is 2.9 m/s2? 1826.2 m/s How far from the surface will a particle go if it leaves the asteroid's surface with a radial speed of 1000 m/s? 713 m With what speed will an object hit the asteroid if it is dropped from 1000 km above the surface? 646.49 m/s Did you conserve the mechanical energy (the sum of the kinetic and potential energies)? Did you use GMm/r for the potential energy (not mgh)? The escape speed is the speed when the escape kinetic energy equals the magnitude of the initial gravitational potential energy. Read the eBook Section 13-6 Gravitation Potential Energy

Explanation / Answer

a)

v = sqrt( 2 g R )

= sqrt ( 2 * 2.9 * 575 * 10^3 )

= 1826.2 m /s

---------------------------------------------------------

b)

rmax = gA rA^2 / (gArA - 1/2Vo^2)

= 2.9 * (575 * 10^3)^2 / (2.9 * 575 * 10^3- 1/2 * 10^6)

= 821 km

h = rmax - rA = 246 km

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.