A technician wraps wire around a tube of length 33 cm having a diameter of 7.8 c

Question

A technician wraps wire around a tube of length 33 cm having a diameter of 7.8 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 560 turns of wire. (a) Find the self-inductance of this solenoid.
1 mH

(b) If the current in this solenoid increases at the rate of 6 A/s, what is the self-induced emf in the solenoid?
2 mV (a) Find the self-inductance of this solenoid.
1 mH

(b) If the current in this solenoid increases at the rate of 6 A/s, what is the self-induced emf in the solenoid?
2 mV

Explanation / Answer

Part A)

Apply (L = mu_{o}N^{2}A/l)

L = (4pi X 10^-7)(560^2)(pi)(.039)^2/.33

L = 5.71 X 10^-3 H which is 5.71 mH

Part B)

Apply (epsilon = LDelta I/Delta t)

EMF = (5.71 X 10^-3)(6) = .0342 V whiich is 34.2 mV

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