A charged particle of mass m = 4.4X10-8 kg, moving with constant velocity in the

Question

A charged particle of mass m = 4.4X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B = 2.2T aligned with the positive z-axis as shown. The particle enters the region at (x,y) = (0.53 m, 0) and leaves the region at (x,y) = 0, 0.53 m a time t = 630 ?s after it entered the region. ) What is Fy, the y-component of the force on the particle at a time t1 = 210 ?s after it entered the region containing the magnetic field. What is q the charge of the particle? what speed did the particle enter the magnetic field? what is Fx at t1= 210 us?

Explanation / Answer

at t=210 secs angle deviated=30 degrees

R=0.53

v=pi*R/2*630 E-6=1320 m/s

force along y- axis=qvBsin(30)=mv^2/R sin(30)=4.4 E-8*1320^2/2*0.53=0.0723 N

force along y- axis=qvBcos(30)=mv^2/R cos(30)=0.125 N

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