1. The ball falls 5.0m from its starting position to reach the level of the targ
ID: 2090250 • Letter: 1
Question
1. The ball falls 5.0m from its starting position to reach the level of the target. The initial y-velocity component is zero, and the acceleration in the y-direction is -10m/s2. Using the y-equation below, you should find that the time interval needed to fall the 5.0m is 1.0s: y - yo = voy t + (1/2)ay t2 Use the horizontal x-motion equation to find the horizontal x-velocity component so that the ball travels 8.0m in the 1.0s falling time. Since ax = 0, x - xo = vox t + 0 2.Choose +4.0m/s for the ball's initial vertical y-velocity component. Decide what initial horizontal x-velocity component will cause the ball to land on the target. (The grid lines are separated by 1.0m, and the gravitational constant is 10m/s2.) After your physics calculations, test your prediction by adjusting the sliders and running the simulation. 3. Choose +10.0m/s for the ball's initial horizontal x-velocity component. Decide what initial vertical y-velocity component will cause the ball to land on the target. (The grid lines are separated by 1.0m, and the gravitational constant is 10m/s2.) After your physics calculations, test your prediction by adjusting the sliders and running the simulation. 4. Choose +11.0m/s for the ball's initial horizontal x-velocity component. Decide what initial vertical y-velocity component will cause the ball to land on the target. (The grid lines are separated by 1.0m, and the gravitational constant is 10m/s2.)Explanation / Answer
1) y = y0 + v0y t + 1/2 a t^2
0 = 5 + 0.5*-10*t^2
5 t^2 = 5
t = 1 s
b) x = v0x t
8 = v0x *1
v0x = 8 m/s
2) you didnt say where the target was but suppose it as it a position d
first find time with y direction
y = y0 + v0y t + 1/2 a t^2
0 = 0 + 4 t - 0.5*10 *t^2
5 t = 4
t = 0.8
so in x direction
d = v * 0.8
v = d/0.8
3) if target is distance d away
d = 10*t
t = d/10
y direction
y = y0 + v0y t + 1/2 a t^2
0 = v*d/10 -0.5*10(d/10)^2
v = 5*d/10 = d/2
4) if target is distance d away
d = 11*t
t = d/11
y direction
y = y0 + v0y t + 1/2 a t^2
0 = v*d/11 -0.5*10(d/11)^2
v = 5*d/11
just plug in the d value to get the numbers for the previous answer
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