Just after a motorcycle rides off the end of a ramp and launches into the air, i

Question

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 7050 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 13900 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 3.30 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Explanation / Answer

Torque T = dL / dT

when there is no torque dL / dT = 0

or L = constant

I w = constant

IE wE = IM wM [E-- engine case, M-- man case]

IE / IM = wM / wE

= 3.30 / 13,900

= 2.37 * 10-4

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