KME-HW9C t Resultant of a General Loading 1 of 2 > Part A Learning Goal To be ab
ID: 2087238 • Letter: K
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KME-HW9C t Resultant of a General Loading 1 of 2 > Part A Learning Goal To be able to find the magnitude and location of a distributed load's resultant force when the distributed load acts on a flat surface A ball pit has the following dimensions: a 1.50 ft, b 18.0 ft , and c 7.50 ft . (Figure 1) The loading on the ball pit's sides is only a function of vertical depth and is given by p- -Cz where C 5.00 lb/ft3 What is FR, the magnitude and location of the resultant force on the ball pit's floor? (Figure 2) Express your answers numerically in pounds and feet to three significant figures separated by commas When a flat surface on the x-y plane is subjected to a distributed load that is defined by the function p p(z,y), the magnitude of the distributed load, FR is the sum of the differential forces acting over the flat View Available Hint(s) FR , Z, ?- 10109.00.3.75 lb,ft, ft Figure 1 of 3> revious Answe Correct Term 1: Significant Figures Feedback: Your answer 1012.5 lb,ft, ft was either rounded differently or used a different number of significant figures than required for this part. Part B For the same ball pit what is the magnitude, FR, and location of the resultant force on the side wall shown? (Figure 3) Express your answers numerically in pounds and feet to three significant figures separated by commas.Explanation / Answer
a)force on the floor=p(z=-a)*area of bottom=(-C*a)*(b*c)=-(-5*1.5)*18*7.5=1012.5lb and it will act at the centroid of the area of the floor that is at x=b/2=9ft and y=c/2=3.75ft.
b)Since the load acts only in vertical direction the force on the side wall will be zero.
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