KHW12-Linear Momentum Item 18 18 of 26 Part A car traveling east and a minivan t
ID: 2040214 • Letter: K
Question
KHW12-Linear Momentum Item 18 18 of 26 Part A car traveling east and a minivan traveling south collide in a completely inelastic collision at a perpendicular intersection. If the initial speed of the 1600 kg car was 76.0 km/h and the initial speed of the 3100 kg minivan was 42.0 km/h, what is the speed of the vehicles immediately after collision? m/s Submit Request Answer Part D What is the direction of the velocity of the vehicles immediately after collision? AX south of east Submit Request AnswerExplanation / Answer
C)
let East be +x axis
let vx and vy are the componenets of velocity after the collsion.
Apply conservation of momentum in x-direction.
vx*(1600 + 3100) = 1600*76
vx = 1600*76/(1600 + 3100)
= 25.87 km/h
Apply conservation of momentum in y-direction.
vy*(1600 + 3100) = 3100*42
vy = 3100*42/(1600 + 3100)
= 27.7 km/h
speed of the vehicles immdediately after the collsion,
v = sqrt(vx^2 +vy^2)
= sqrt(25.87^2 + 27.7^2)
= 37.9 km/h
= 37.9*5/18
= 10.5 m/s <<<<<<<<<<----------------Answer
D) direction : theta = tan^-1(vy/vx)
= tan^-1(27.7/25.87)
= 47.0 degrees south of east <<<<<<<<<<----------------Answer
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