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03. [10 marks] In the single cylinder example (crank-slider) discussed in class,

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Question

03. [10 marks] In the single cylinder example (crank-slider) discussed in class, the crank rotates at a speed of 1000 rpm. The crank OA has a length of 102 mm, a mass of 4.54 kg, and center of mass located at 38.1 mm from O. The connecting rod AB has a length of 356 mm, a mass of 15.4 kg, and center of mass located at 102 mm from A. The piston has a mass of9.1 kg. (i) Calculate the equivalent mass of the connecting rod at each of its ends, calculate the equivalent mass of the crank at each of its ends. (ii) Determine the rotating counterbalance (mass times eccentricity) that must be added to the crank to balance the rotating mass of the crank and portion of the (iii) Calculate the maximum value of the shaking force after the balance in (ii) has (iv) If the maximum primary shaking force is to be reduced by half, determine the connecting rod, i.e. eliminating the transverse shaking force. been achieved. rotating counterbalance that should be added to the crank to achieve this. What is the maximum shaking force after the rotatileg counterbalance is added? Fig Q3

Explanation / Answer

i) eq. massrot = masscr * distance from crank pin / length of cr = 15.4 * 0.102/ 0.356 = 4.4kg

eq. massrev = masscr * distance from piston pin / length of cr = 15.4 * (0.356- 0.102)/ 0.356 = 10.99kg

eq. massrot = massck * distance from centre / length of crank = 4.54* 0.0381 / 0.102 = 1.69kg

eq. massrot = massck * distance from crank pin / length of crank = 4.54 * (0.102-0.0381)/ 0.102 = 2.84kg

ii)