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023 (part 1 of 2) 10.0 points A solenoid 112.2 cm long has 420 turns and a radiu

ID: 1722149 • Letter: 0

Question

023 (part 1 of 2) 10.0 points A solenoid 112.2 cm long has 420 turns and a radius of 2.88 cm. The permeability of free space is 1.25664 × 106 N/A2. If it carries a current of 1.5 A, find the magnetic field along the axis at its center. Answer in units of T. 024 (part 2 of 2) 10.0 points Calculate the magnetic field on the solenoidal axis at the end of the solenoid. Answer in units of T. 023 (part 1 of 2) 10.0 points A solenoid 112.2 cm long has 420 turns and a radius of 2.88 cm. The permeability of free space is 1.25664 × 106 N/A2. If it carries a current of 1.5 A, find the magnetic field along the axis at its center. Answer in units of T. 024 (part 2 of 2) 10.0 points Calculate the magnetic field on the solenoidal axis at the end of the solenoid. Answer in units of T.

Explanation / Answer

   The magnetic field along the axis at itscenter is           B =o NI/L Here o =1 .25664 × 106 N/A2.           N =420            I= 1.5 A           L =0.1122 m 024 ) The magnetic field on the solenoidal axis atthe end of the solenoid is                 B = o NI/(2L) Substitute the values for B.