The figure below shows the cross-section of a long offset rectangular coaxial ca

Question

The figure below shows the cross-section of a long offset rectangular coaxial cable (much like the one you analyzed in the finite-difference project for this course). The inner conductor is held at 50 V and the outer conductor is at 0 V. An electric field will exist in the space between the two conductors. Suppose you sample the E field at the two positions, point P_1 and point P_2 shown in the figure below. Which of the following statements is true? Most likely, the E-field magnitude is larger at point P_1 compared to P_2. This is because the electrostatic potential changes slowly from 50 V to 0 V in region around P_1, i.e. gradient of V is smaller at P_1. Most likely, the E-field magnitude is about the same at points P_2 and P_1 since both points are about the same distance to the 0V conductor. Most likely, the E-field magnitude is zero at both points P_2 and P_1 since both points are close to the 0V conductor. Most likely, the E-field magnitude is larger at point P_2 compared to P_1. This is because the electrostatic potential changes rapidly from 50 V to 0 V in region around P_2, i.e. gradient of V is larger at P_2.

Explanation / Answer

Answer:- Option D is correct.

we know magnitude of electric field is given by the rate of change of electric potential, i.e |E| = dV/dr.

At point P2 the rate of change of potential is faster than point P1. The potential change is rapid from 50 V to zero in a small change of distance 'r'.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.