A sin function with an argument equal to 2*pi* 10? radians/sec can represent a s

Question

A sin function with an argument equal to 2*pi* 10? radians/sec can represent a signal with a frequency of A. []2*pi Hz B.[] 2*pi*10^7 Hz C. [] 10 MHz D. [] None of the above If the phasor, Ae^-alpha x e^j(alpha x + beta x), represents a voltage on a transmission line where alpha, beta are omega are real numbers and alpha > 0, beta > 0, omega > 0 then the time waveform is A. [] propagating in the +x direction with an increasing amplitude B. [] propagating in the +x direction with a decreasing amplitude C. [] propagating in the -x direction with an increasing amplitude D. [] propagating in the -x direction with a decreasing amplitude If a_1 = 1 and S_11 = 5 for the device under test (DUT) then one can infer A. [] a_2 = 5 when b_1 = 0 B. [] b_2 = 5 when b_1 = 0 C. [] b_1 = 5 when a_2 = 0 D. [] None of the above S_1 and S_2 are s-matrices for two circuits cascaded together as shown R_1 and R_2 are R matrices defined using the m-files indicated. The s-matrix for the cascaded circuit using MATLAB equals A. [] S_ = inv(R_1*R_1*R) B. [] S_ = t2s(R_1*R_2) C. [] S_ = S_1*S_2 D. [] S_ = R_1*R_2 The s-matrix for a matched -20dB attenuator would equal A. (0 1 1 0) B. (.01 0 0 01) C. (10 -10 -10 10) D. (20 -20 -20 20)

Explanation / Answer

According to Chegg policy, Only question 6 is answered.

Argument is of the form (2*pi * f) so comparing to the 2 * pi * 10^7 radians / sec.

f = 10^7 radians / sec

so

f = 10 * 10^6 radian/sec

= 10 M Hz

So answer is C

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