1)Thoroughly explain how the amplifier works. Include explanations of why the ou
ID: 2084712 • Letter: 1
Question
1)Thoroughly explain how the amplifier works. Include explanations of why the output wave is inverted compared to the input wave, why clipping occurs at V_out amplitude somewhat below V_cc and somewhat higher than ground.
2) Explain in detail how adding an unbypassed portionof Re controls the gain. What advantages might this technique provide?
3) Anything else deemed pertinent?
Thank you in advance,
A
xSC1 Ext Vout Rc Rbl Q1 2N3904 luF Cc 15V T Vcc Cb 20mVpk Rb2 )10kHiz Re 0° Vin Ce Figure 1: Stiff Bias Common Emitter AmplifierExplanation / Answer
in the diagram Rb1 and Rb2 are act as voltage divider bias circuit. aspecially in amplifiers for maintaing operating point biasing is required. and in common emitter amplifier out put always 180 degrees out of phase to input. i willexplain this with small equation ie Vce= Vcc-IcRc
let us take positive half cycle of input it gradually increses from zero reference then collector current isincreased so in the above equation IcRc term increses then output becomes negative opposite action is possible for negative half cycle. clipping is generally occured if the transistor enterd in saturation or cutoff regions.
Re resistor provides negative feed back to the circuit as we already know negative feed back provide more stabilization. it nullify any changes in collector current
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