Latex does not work, not sure why, but the equation is this, the charge going in

Question

Latex does not work, not sure why, but the equation is this, the charge going into a circuit element expression:

q(t) = q(t_o) + integral from lower limit t_o to upper limit t, of ( i(Tau)dTau )

So I want to inegrate i(Tau)=2 with q(t_o) = 0 and with limits which are known to me, and so it goes:

q(t) = 0 + integram from lower limit t_o = 2 to upper limit t = t, of ( (2)dTau )

and so I integrate this constant and then I get:

q(t) = 2Tau and now I plug in my limits in for Tau, BUT my question is:

How can I plaug in a value of t in for Tau? Is it because Tau is an element of t? I am so confused please help guys!

Much Thanks

Explanation / Answer

There is an integral property,

you can change the differentiating quantity in the integral i.e Tau in this case if you are changing the same quantity in the function itself i.e i (Tau ) in this case.

so you can replace Tau by t and there is nothing wrong with this.

So, The final answer also will be same.

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.