D) using ampere law , calculate the magnetic field inside the conductor at r= R/

Question

D) using ampere law , calculate the magnetic field inside the conductor at r= R/2 = 1.25 cm E) what is the magnetic field on the axis of the conductor (r=0)? Problem 8. A cylindrical conductor of radius R -2.5 cm carries a steady current Io 2.5 A that is uniformly distributed over the cross-section of the wire as shown in the figure. (a) (8 points) Using Ampere's law, Find the magnetic field outside the conductor at r =2R = 5 cm. (b) (2 points) what is the magnetic field infinitely far away from the conductor ( r )? (c) (2 points) Calculate the current density (current per unit cross-sectional area; unit: A/m') in the conductor

Explanation / Answer

D)Magnetic Field inside the given radius the equation is

B = µIr / 2*3.14*a^2 where r= 1.25cm=.0125m

And a=2.5cm= .025m

So B = 4*3.14*10^-7*2.5*.0125/2*3.14*(.025^2)

B= 1*10^-5 Tesla inside the conductor

E)magnetic field on axis of conductor will be zero.

C) current density J = I/A = 2.5/3.14*(.025^2)=12560 A/m^2

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.