A uniformly charged disk of radius 35.0 cm carries a charge density of 6.90 10-3

Question

A uniformly charged disk of radius 35.0 cm carries a charge density of 6.90 10-3 C/m2. Calculate the electric field on the axis of the disk at the following distances from the center of the disk.

A uniformly charged disk of radius 35.0 cm carries a charge density of 6.90 x 10 3 c/m2. Calculate the electric field on the axis of the disk at the following distances from the center of the disk. (a) 5.00 cm Your response differs from the correct answer by more than 100%. MN/C (b) 10.0 cm MN/C (c) 50.0 cm MN/C (d) 200 cm MN/C

Explanation / Answer

electric field due to a charged disc= 2k(1-x/(x^2+r^2) ) where k=9*10^(9) r=.35   =6.9*10^(-3)

where r= radius and x=distance from the central point

hence electric field= 378684000*(1-x/(x^2+r^2) )

at 5cm field=334.84 MN/C

at 10 cm field= 282.85 MN/C

at 50 cm field=70.50 MN/C

at 200 cm field=5.84 MN/C

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