A uniformly charged disk of radius 35.0 cm carries a charge density of 7.40 x 10

Question

A uniformly charged disk of radius 35.0 cm carries a charge density of 7.40 x 103 C/m2. Calculate the electric field on the axis of the disk at the following distances from the center of the disk. (a) 5.00 cm 3.55 10*8X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. MN/C (b) 10.0 cm 033 10x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. MN/C (c) 50.0 cm 7.52 107 Your response differs from the correct answer by more than 100%. MNC (d) 200 cm 6.27 106x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. MN/C

Explanation / Answer

equation for the electric field of a charged disk, which is:

E = ( / 2) * {1 - [z / (z^2 + r^2)]}

where,
E = Electric Field
= Charge Density of the Disk (7.40*10^-3 C/m^2)
= Permittivity of Free Space (8.85*10^-12 C^2/Nm^2)
z = Radial distance from the center of the Disk
r = Radius of the Disk (0.350 m)

put z= 0.05 in (a), z= 0.10 in (b), z= 0.5 in (c) & z= 2 in (d) and calculate

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