While attempting to tune the note C at 523 Hz, a piano tuner hears 2 beats/s bet

Question

While attempting to tune the note C at 523 Hz, a piano tuner hears 2 beats/s between a reference oscillator and the string. (a) What are the possible frequencies of the string? (b) When she tightens the string slightly, she hears 3 beats/s. What is the frequency of the string now? (c) By what percentage should the piano tuner now change the tension in the string to bring it into A student holds a tuning fork oscillating at 256 Hz. He walks toward a wall at a constant speed of 1.33 (a) What beat frequency does he observe between the tuning fork and its echo? (b) How fast must he walk away from the wall to observe a beat frequency of 5 Hz?

Explanation / Answer

a) possible freq = 523 + 2= 525Hz or 523 -2 =521Hz

since beat freq = difference between two frequencies..

b)when tightened the the length decreases,,so freqincreases..

frequency of string = 526Hz..so that beatfreq = 526 - 523 = 3

c) f T

so f1/f2 = T1/T2 =

T1 = 0.998T2

% change will be negative = -1.13

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