Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(4) Proton radiation therapy is used to bombard a tumor at a certain tissue dept

ID: 2076491 • Letter: #

Question

(4) Proton radiation therapy is used to bombard a tumor at a certain tissue depth with protons. We consider how protons slow down in body tissue. Let A deonte atomic mass of absorber, 2 the atomic number of incident particle Z the atomic number of absorber, I the material-dependent characteristic ionization constant, Tmaar the maximum kinetic energy transfer, S(Br) is density effect correction to ionization energy loss, and B and Y capture the relativistic effects of the incident particles. In the first table, we provide data on proton energy loss per pentration depth using the Bethe-Block formula for water. dE Z 1 Kz A B2 2 dr

Explanation / Answer

ANS:-              Photon energy (MeV)                       Energy Loss(MeV)

                  3.          144.56                                             5.644

                  4.         195.51                                             4.567

                  5           296.48                                             3.558

                 6           396.98                                            3.035

                7             497.26                                           2.747

                8             597.45                                         2.559

                9            697.58                                          2.428      

                10          797.67                                          2.339    

                11           897.74                                         2.258

                 12          997.79                                         2.206

                13           1997.95                                       2.050

                 14         3997.91                                        2.011            

So table is compleated.

as per liner interpoler method . value is not give in this Question.

but generally to interpolate the y2 value
x1, x3, y1 and y3 are to be need from table.
x2 defines as a point to interpolation perform.
y2 is interpolated solution & value

x1

y1

x2

y2

x3

y3

           

x1

y1

x2

y2

x3

y3