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9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pres

ID: 2075878 • Letter: 9

Question


9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure
9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure
9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure

Explanation / Answer

Force on each tire = mg/2 <---- as the whole weight needs to be divided equally between the two tires

Now, pressure on each tire , P = F/A = mg/(2A)

So, P = (1.013*10^5 + 1.2*10^6) = mg/2A

So,  (1.013*10^5 + 1.2*10^6) = 15*9.8/(2*A)

So, A = 5.65*10^-5 m2 <---------answer

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