A 3.00 kg objects slides on a horizontal surface when acted on by a force of 12.

Question

A 3.00 kg objects slides on a horizontal surface when acted on by a force of 12.0 N supplied by a cord that is attached to the object and make an angle of 20 above the horizontal and a force of friction of 2.0 N. Calculate the normal force ehe surface exerts on the object. The acceleration along the surface. A 3.00 kg objects slides on a horizontal surface when acted on by a force of 12.0 N supplied by a cord that is attached to the object and make an angle of 20 above the horizontal and a force of friction of 2.0 N. Calculate the normal force ehe surface exerts on the object. The acceleration along the surface.

Explanation / Answer

Here ,

f = 2 N

m = 3 Kg

F = 12 N

theta = 20 degree

for the normal force

N = m * g - F * sin(20 degree)

N = 3 * 9.8 - 12 * sin(20 degree)

N = 25.3 N

the normal force the surface exerts on the object is 25.3 N

for the acceleration of the block

3 * a = 12 * cos(20) - 2

a = 3.1 m/s^2

the acceleration of the block is 3.1 m/s^2

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