The ABC Manufacturing Company owns 9 buildings (symbolized as A, B, C, D, E, F,
ID: 2074450 • Letter: T
Question
The ABC Manufacturing Company owns 9 buildings (symbolized as A, B, C, D, E, F, G & H. These buildings are already constructed, so inter-building distance are fixed as given in the From-To chart. Each building will be the shop for one type of operation only. The process sequence is given in the Table below. The maximum load for the material handling is 100 Kg.
Each building is of equal area
Methods of production control specify the sequence of operations and indicate that they are not to be changed.
Product mix remains stable (No. products of each variety is fixed)
The prime measure of effectiveness of the layout is the sum of the products of Quantity multiplied by the weight of each part multiplied by the distance traveled.
Question: Construct a travel chart and determine the total number of loads/week.
Routing Summary
Part No.
Quantity/week
Weight Kg.
Operation Sequence
Operations:
(r) Raw Material Stores
(p) Pattern Shop
(f) Foundry
(w) Welding
(d) Drilling
(l) Lathes & Planers
(m) Milling
(i) Inspection
(g) Finished Parts Stores
1
5000
1
r - p - l - d - m- i - g
2
3000
0.4
r - w - l - m - d - i - g
3
2500
2
r - p - l - i - g
4
1000
3
r - p - f - m - i - g
5
3500
1.5
r - p - f - g
6
4000
2.5
r - m - d - l - w - i - g
7
1500
0.4
r - l - d - m - i - g
8
2500
2.5
r - l - m - i- d - w - g
9
4500
1.5
r - w - m - l - d - i - g
A B C D E F G H I A 20 30 40 25 50 60 80 100 B 25 30 40 30 60 50 70 C 40 20 35 50 40 60 D 30 50 40 30 50 E 40 70 50 70 F 50 60 50 G 40 60 H 20Explanation / Answer
A(r)
B(p)
C(f)
D(w)
E(d)
F(l)
G(m)
H(i)
I(g)
A(r)
(5000*1+2500*2+1000*3+3500*1.5)*20=365000
(3000*0.4+4500*1.5)*40=
318000
(1500*0.4+2500*2.5)*50=
342500
4000*2.5*60=
600000
B(p)
(1000*3+3500*1.5)*25=
206250
(5000*1+2500*2)*30=
300000
C(f)
1000*3*50=
150000
3500*1.5*60=
315000
D(w)
3000*0.4*50=
60000
4500*1.5*40=
270000
4000*2.5*30=
300000
2500*2.5*50=
312500
E(d)
2500*2.5*30=
187500
4000*2.5*40=
400000
(5000*1+1500*0.4)*70=
392000
(3000*0.4+4500*1.5+4500*1.5)*50=
735000
F(l)
4000*2.5*50=
500000
(5000*1+1500*0.4+4500*1.5)*40=
494000
(3000*0.4+2500*2.5)*50=
372500
2500*2*60=
300000
G(m)
(3000*0.4+4000*2.5)*70=
784000
4500*1.5*50=
337500
(5000*1+1000*3+1500*0.4+2500*2.5)*40=
594000
H(i)
2500*2.5*50=
312500
(5000*1+3000*0.4+2500*2+1000*3+4000*2.5+1500*0.4+4500*1.5)*20=
631000
I(g)
Total=365000+318000+342500+600000+206250+300000+150000+315000+187500+400000+392000+735000+500000+494000+372500+784000+337500+594000+312500+631000=8336750
A(r)
B(p)
C(f)
D(w)
E(d)
F(l)
G(m)
H(i)
I(g)
A(r)
(5000*1+2500*2+1000*3+3500*1.5)*20=365000
(3000*0.4+4500*1.5)*40=
318000
(1500*0.4+2500*2.5)*50=
342500
4000*2.5*60=
600000
B(p)
(1000*3+3500*1.5)*25=
206250
(5000*1+2500*2)*30=
300000
C(f)
1000*3*50=
150000
3500*1.5*60=
315000
D(w)
3000*0.4*50=
60000
4500*1.5*40=
270000
4000*2.5*30=
300000
2500*2.5*50=
312500
E(d)
2500*2.5*30=
187500
4000*2.5*40=
400000
(5000*1+1500*0.4)*70=
392000
(3000*0.4+4500*1.5+4500*1.5)*50=
735000
F(l)
4000*2.5*50=
500000
(5000*1+1500*0.4+4500*1.5)*40=
494000
(3000*0.4+2500*2.5)*50=
372500
2500*2*60=
300000
G(m)
(3000*0.4+4000*2.5)*70=
784000
4500*1.5*50=
337500
(5000*1+1000*3+1500*0.4+2500*2.5)*40=
594000
H(i)
2500*2.5*50=
312500
(5000*1+3000*0.4+2500*2+1000*3+4000*2.5+1500*0.4+4500*1.5)*20=
631000
I(g)
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