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The A-36 steel shaft is 3 m long and has a diameter of 50mm. It is required to t

ID: 1815445 • Letter: T

Question

The A-36 steel shaft is 3 m long and has a diameter of 50mm. It is required to transmit 35 kW of power from the engineE to the generator G. Determine the smallest angular velocitythe shaft can have if it is restricted not to twist more than1degree.

Explanation / Answer

= TL/JG where T=torque L=3m,r=0.025m J=pr4/2=>J=6.13*10-7m^4 G=79.3Gpa =1degree=/180 power, P=35kW so, T=JG/L T=6.13*10-7*79.3*109*/(180*3) T=2.828*102Nm we know that power P=torque * angular velocity so, angular velocity, =35*103/2.828*102 angular velocity,=123.76 radians/sec (check for calculations,but this is the procedure)

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