LOOKUP TABLES - The amount of energy required to change 1 kg of liquid water at
ID: 2073825 • Letter: L
Question
LOOKUP TABLES - The amount of energy required to change 1 kg of liquid water at a constant pressure complete to vapor is called the enthalpy of vaporization ( ). Calculate the amount of heat required Q to change a mass, m, of water from liquid to vapor at a constant pressure given by .
Make a table using the pressure and enthalpy of vaporization data on Below. Put the data on one worksheet.
On another worksheet, have a cell for users to enter a temperature and another cell to enter a mass. Use LOOKUP TABLES FORMULAS to calculate the heat of vaporization.
Finally, calculate the amount of heat required Q to change the mass from liquid to vapor.
Pressure Enthalpy of Vaporization Temperature 0 25 50 75 100 125 150 175 200 225 250 275 300 325 350 375 0.6613 3.169 12.35 38.58 101.4 232.1 475.8 892 1554 2548 3973 5942 8581 12060 16510 22090 2501 2442 2383 2321 2257 2189 2114 2052 1941 1837 1716 1575 1405 1190 893 0Explanation / Answer
* Result shows that with increase in pressure, saturation or boiling temperature increases but heat required to covert liquid in water per unit of mass decreases and it become zero at 22090 units of pressure, this point is known as critical point.
LOOKUP TABLE Sr. No. Temperature(T) Pressure(P) Enthalpy of Vaporization(h) (kJ/Kg) Mass(m)(Kg) Heat require (kJ), Q= Mass* Enthalpy of vaporization= m*h 1 0 0.6613 2501 1 =1*2501 2 25 3.169 2442 so on Use same formula 3 50 12.35 2383 so on Use same formula 4 75 38.58 2321 --- ------ 5 100 101.4 2257 ---- ---- 6 125 232.1 2189 ----- ------ 7 150 475.8 2114 ----- ------ 8 175 892 2052 -------- ----------- 9 200 1554 1941 ------ -------------- 10 225 2548 1837 ------- --------------- 11 250 3973 1716 ---------- ------------ 12 275 5942 1575 ----------- ------------ 13 300 8581 1405 ------- ------------ 14 325 12060 1190 ----------- -------- 15 350 16510 893 ------- ----------- 16 375 22090 0 ------ 0Related Questions
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