LON-CAPA A Dizzy Stroll × ? e A CD Has A Mass 0117 G An XV LON-CAPA Menu d . Sec
ID: 2033224 • Letter: L
Question
LON-CAPA A Dizzy Stroll × ? e A CD Has A Mass 0117 G An XV LON-CAPA Menu d . Secure https: capa9.phy ohio edures/ohiou0Up200lib/sfChpt8/sf0807a.problem?symb-uploaded%2fohou%2f91391804 150295a49oucapa2%2fdefault_135091 7821 %2esequen. ? ? Megan Michalak(Student- section: 101) Physics 2001/Spring 2018 l Messages Courses Help Logout Main Menu Contents Grades Course Contents» * Assignment 10A Dizzy Stroll O Timer ?Notes Evaluate EeFeedback-Print Info A Dizzy Stroll Due this Friday, Mar 30 at 11:59 pm (EDT) A horizontal circular platform m = 53.1 kg, r = 3.11m rotates about a frictionless vertical axle. A student m-83.3kg walks slowly from the rim of the platform toward the center. The angular velocity, omega, of the system is 2.5 rad/s when the student is at the rim. Find omega when the student is 2.81m from the center 2.50 radv's Remember to conserve angular momentum of the system both before and after the student moves. Submit Answer Incorrect. Tries 1/10 Previous Tries his discussion is closed ?Send FeedbackExplanation / Answer
let
M = 53.1 kg, R = 3.11 m
m = 83.3 kg, r = 2.81 m
wi = 2.5 rad/s
wf = ?
Apply conservation of angular momentum
If*wf = Ii*wi
(0.5*M*R^2 + m*r^2)*wf = (0.5*M*R^2 + m*R^2)*wi
==> wf = (0.5*M*R^2 + m*R^2)*wi/(0.5*M*R^2 + m*r^2)
= (0.5*53.1*3.11^2 + 83.3*3.11^2)*2.5/(0.5*53.1*3.11^2 + 83.3*2.81^2)
= 2.90 rad/s <<<<<<<------------------Answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.