Exercise 2: An idealized model of a fuselage shown in Figure 2 has six stringers

Question

Exercise 2: An idealized model of a fuselage shown in Figure 2 has six stringers, where each having an area of 300 mm2. The model is subjected to a vertical load of 5o kN and a horizontal load of 20 kN acting at the centroid of the fuselage model (a). Determine the shear flow distribution in the model (show them in clear sketch with proper direction of the flow). (b). If the maximum allowable shear stress on the floor (panel 1-2 and 6-1) is 4 MPa, determine the minimum required thickness of the floor panel to sustain the current loading condition. P, 1000 1000 500 866.025866.025 Figure 2

Explanation / Answer

The bending moment M = 6.2 x 106 lb.in therefore, for one a perpendicular distance of one inch

M = F x d = F x 1in = F

M = F = 6.2 x 106 lb where F is the applied force.

The normal stress of the stringer is 72 ksi, the normal stress is given by

N = F/A , which implies,

A = F/N = 6.2 x106 / 72 = 0.0861 x 10 6 in2 = 86.1 x 103 in2, therefore the area A1 of the stringer is 86.1 x 103 in2 . Since the area A1 is calculated, we can find the area A2 = 2A1 = 2 x 86.1 x 103 = 172.2 x 103 in2 and area A3 = 1.4 A1 = 1.4 x 86.1 x 103 = 120.54 x 103 in2. Due to symmetry of the wingbox along the y-axis, the areas A6 , A5 , A4 will equal to areas A1 , A2 , A3 respectively.

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.