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Exercise 26.42 A 12.4? ? F capacitor is connected through a 0.885?M? resistor to

ID: 1374480 • Letter: E

Question

Exercise 26.42

A 12.4??F capacitor is connected through a 0.885?M? resistor to a constant potential difference of 60.0 V.

Part A

Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

Part B

Compute the charging currents at the same instants.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

Explanation / Answer

V(t) = V0 [ 1 - e^(-t /RC) ]

V(t) = 60 [ 1 - e(-t / 10.97)]

Part (A)

V(0) = 0

V(5) = 60 [ 1 - e(-5 / 10.97)] = 21.96 V

V(10) = 60 [ 1 - e(-10 / 10.97)] = 35.88 V

V(20) = 60 [ 1 - e(-20 / 10.97)] = 50.310 V

V(100) = 60 [ 1 - e(-100 / 10.97)] = 59.99 V


Part (B)

I(t)*R = IR [ 1 - e(-t / 10.97)]

I(t) = (6.78 x 10^-5) [ 1 - e(-t / 10.97)]

I(0) = 0

I(5) = (6.78 x 10^-5) [ 1 - e(-5 / 10.97)]   = 2.48 x 10^-5 A

I(10) = (6.78 x 10^-5)[ 1 - e(-10 / 10.97)] = 4.05 x 10^-5 A

I(20) =(6.78 x 10^-5)[ 1 - e(-20 / 10.97)] = 5.68 x 10^-5 A

I(100)= (6.78 x 10^-5)[ 1 - e(-100 / 10.97)] = 6.78 x 10^-5 A