An 85 kg worker at a breeder reactor plant accidently ingest 0.25 mg of 239 Pu (

Question

An 85 kg worker at a breeder reactor plant accidently ingest 0.25 mg of 239 Pu (239.0521u) dust. This isotope has a half-life of 24, 100 year decaying by alpha decay. The energy of the emitted alpha particle (4.001u) is 5.2 MeV with a RBE of 13. Assume plutonium resides in the workers body for 12 hours and that 95% of the emitted alpha particles are stopped by his body. What is die initial activity of the sample? 5.36 times 10^5 Bq 5.74 times 10^5 Bq 8.29 times 10^5 Bq 4.14 times 10^7 Bq 9.60 times 10^9 Bq What is the resulting physical dose? 267rad 2.7rad 1.0rad 0.94rad 0.230rad Assuming you got the answer to the previous question correct. How would you get the dose equivalent given to the worker in Rem? multiply by 85 multiply by 5.2 multiply by 13 A moderator in a nuclear reactor is used to increase the energy of the protons decrease the energy of the protons decrease the energy of neutrons decrease the number of beta particles moderate the wave length of the photons The moderator used in almost all US nuclear reactors is Water Boron Uranium-235

Explanation / Answer

49)a moderataor is used to decrease energy of neutrons

50)commonly used moderators include regular (light) water (roughly 75% of the world's reactors), solid graphite (20% of reactors) and heavy water (5% of reactors).

48)multiplied by13

47)resulting physical dose=1.0rad

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.