An 80 kg skier starts with a speed of 1 m/s at the top of a slope and skis down

Question

An 80 kg skier starts with a speed of 1 m/s at the top of a slope and skis down from a vertical elevation of h=20 m. The speed of the skier at the bottom of the slip is 10 m/s. Theta = 5.74 degrees.

What is the gravitational potential energy in joules of the skier when located at the top of the slope and the Kinetic energy in joules of the skier located at the top of the slope.

What is the kinetic energy in joules of the skier at the bottom of the slope.

How much work in joules is done by friction on the slope along with how much frictional force in newtons is acting on the skier?

Explanation / Answer

gravitational potential energy = final kinetic energy-initial kinetic energy
= 80 x 102/2- 80 x12/2

=3960 J

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