<div id=\"MathJax_Message\" style=\"display: none; \"></div><p>A small wooden bl

Question

<div id="MathJax_Message"></div><p>A small wooden block with mass 0.850 kg is suspended from the lower end of a light cord that is 1.54 m long. The block is initially at rest. A bullet with mass 0.0104 kg is fired at the block with a horizontal velocity <span class="formula"><span class="math_text_before">&nbsp; &nbsp;</span><span class="jax_wrap finalized_jax" data-jax="v_{0}"><span class="MathJax_Preview"></span><span class="MathJax" role="textbox" aria-readonly="true"><nobr><span class="math" id="MathJax-Span-59"><span><span><span class="mrow" id="MathJax-Span-60"><span class="msubsup" id="MathJax-Span-61"><span><span><span class="mi" id="MathJax-Span-62">v</span><span></span></span><span><span class="texatom" id="MathJax-Span-63"><span class="mrow" id="MathJax-Span-64"><span class="mn" id="MathJax-Span-65">0</span></span></span><span></span></span></span></span></span><span></span></span></span><span></span></span></nobr></span><script type="math/tex" id="MathJax-Element-14">v_{0}</script> <sup href="#" class="formula_delete" data-mce-href="#">X</sup><sub href="#" class="formula_edit" data-mce-href="#">Edit</sub></span><span class="math_text_after">&nbsp; . The bullet strikes the block and becomes embedded in it. After the collision the combined object swings on the end of the cord. when the block has risen a vertical height of 0.800 m, the tention in the cord is 4.72 N.</span></span></p>

Explanation / Answer

as the bullet hits its ke gets converted to Pe T=mgcos +mvv/r hence 475 m/s is the velocity after solving

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