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All four bulbs are identical and have resistance R . The two batteries are ident

ID: 2069017 • Letter: A

Question


All four bulbs are identical and have resistance R. The two batteries are identical and maintain a potential difference (EMF) = E. Answer the following questions and explain why you believe your answer. (Most bulbs are brighter when there is more current through them. Assume that is the case for these bulbs.)

Consider the two arrangements of batteries and bulbs shown.

All four bulbs are identical and have resistance R. The two batteries are identical and maintain a potential difference (EMF) = E. Answer the following questions and explain why you believe your answer. (Most bulbs are brighter when there is more current through them. Assume that is the case for these bulbs.)


Explanation / Answer

1. In system 1, which bulb is brighter?

          they have the same brightness, since they are in series and have the same current

2. In system 1, what is the current through each bulb, the voltage drop across each bulb, and the power dissipated by each bulb?

   current through each = E / 2R

   voltage drop = E/2

   power dissipated = current * voltage = E^2 / 4R

3. In system 2, which bulb is brighter?

They have the same brightness, since they are identical.

4. In system 2, what is the current through each bulb, the voltage drop across each bulb, and the power dissipated by each bulb?

current through each = E/R

voltage drop = E

   power = E^2 / R

5. Which bulbs are brighter, those in system 1 or those in system 2?

   System 2, since they have higher current

6.If one bulb in each system burns out, will the other go out as well? Why? If the other bulb doesn't go out will it get brighter or stay the same when the first bulb in the circuit burns out?

   System 1: yes, other bulb goes out, the circuit is broken

   System 2: no, other bulb does not go out since it is still connected to the battery. It will stay the same as it was before (not brighter or dimmer).

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