Large conventional electromagnets use water cooling to prevent excessive heating

Question

Large conventional electromagnets use water cooling to prevent excessive heating of the magnetic coils. A large laboratory electromagnet has a current of 100A when a voltage of 240V is applied to the terminals of the energizing coils. To cool the coils, water at an initial temperature of 15 degrees celsius is circulated around the coils. How many liters of water must circulate by the coils each second if the temperature of the coils is not to exceed 50 degrees celsius?

Explanation / Answer

Power = Voltage*Current = 240*100 This should be equal to the heat absorbed by the water specific heat of water = 4.186 J/g c 24000 = M*4.186*(50-15) => M = 163.81grams Taking density of water as 1 g/ml we get 0.164 liters of water should circulate per second

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